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Can shaking make an upside-down pendulum stable? Yes, if the pivot vibrates up and down rapidly enough. Averaged over the fast shaking, the motion feels an extra effective force pushing it toward the upright position, so the inverted state becomes stable. Pyotr Kapitza analysed this effect. Kapitzar balances on that buzzing rod. Pixel-art unisex tee; equation, symbols and sources in the physics panel below.

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Size guideS–5XL · inches

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Size & fitS–5XL

Unisex heavy cotton (Gildan 5000), classic fit.

Unisex tee size chart, inches
SizeWidthLengthSleeve
S182815.1
M202916.5
L223018
XL243119.5
2XL263221
3XL283322.4
4XL303423.7
5XL323525

Measurements in inches, ±1.5 in tolerance.

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Returns & replacements21 days

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The physics

Balance a pendulum upside down and it falls. Vibrate its pivot up and down fast enough and it stands.

Averaged over the fast shaking, the pendulum feels an extra potential that pulls it towards the vertical. When the pivot's speed beats the square root of 2gl, the inverted position becomes a stable dip. Pyotr Kapitza explained it in 1951.

Kapitzar stands on a buzzing base. Buzz the base. I stand.

Equations

\[U_{\text{eff}}(\theta) = -m g l\cos\theta + \frac{m a^{2}\omega^{2}}{4}\sin^{2}\theta\]
\[a^{2}\omega^{2} > 2\,g\,l\;\;\Rightarrow\;\;\theta = \pi\ \text{(upside down) is stable}\]
Symbols
SymbolMeaningUnit
\(U_{\text{eff}}\) time-averaged effective potential of the pendulum \(\mathrm{J}\)
\(\theta\) angle from the hanging-down position \(\mathrm{rad}\)
\(m\) mass of the bob \(\mathrm{kg}\)
\(g\) gravitational acceleration \(\mathrm{m/s^2}\)
\(l\) length of the pendulum \(\mathrm{m}\)
\(a\) amplitude of the pivot's vertical vibration \(\mathrm{m}\)
\(\omega\) angular frequency of the pivot vibration \(\mathrm{rad/s}\)

Sources

  1. Butikov (2001) On the dynamic stabilization of an inverted pendulum, Am. J. Phys. 69, 755 (opens in a new tab)
  2. Kapitza (1951) Dynamic stability of a pendulum when its point of suspension vibrates, Zh. Eksp. Teor. Fiz. 21, 588 (citation only)
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