• Pixel-art sticker of Swoopet, personifying Brachistochrone, with the caption “Not The Short Way, The Fast Way.”

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Swoopet

Brachistochrone Physics

\[t = \pi\sqrt{\frac{r}{g}}\]
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Meet Swoopet, a rolling ball who knows the shortest path is not always the fastest. Johann Bernoulli posed the brachistochrone in 1696; the answer is a cycloid that drops steeply first. For a 1 m wheel radius, the descent takes about 1.0 s from any starting point. Pixel-art kiss-cut sticker in 2, 3, 4 and 6 inches; equation, symbols and sources in the physics panel below.

Size
Surface

Flat $6 shipping worldwideMade to order, ships in 2–5 business days

Details

Size3″ × 3″

3″ × 3″ kiss-cut sticker.

Shipping

Flat $6 shipping on every order, worldwide, whatever's in it.

Delivery times & where we ship

Returns & replacements21 days

Every item is printed to order, so we can’t accept returns or exchanges for change of mind, or if you ordered the wrong size or colour.

Print defect, misprint, damage or the wrong item? We’ll send a free replacement, or a refund if you prefer. Report it within 21 days of delivery with a photo; no need to send it back.

Full refund & replacement policy

The physics

Meet Swoopet, a rolling ball who knows that the shortest path is not always the fastest.

In 1696 Johann Bernoulli challenged the best mathematicians of Europe. Which curve lets a bead slide from one point to a lower point in the least time, under gravity alone? The answer is called the brachistochrone, from the Greek for shortest time.

A straight line is the shortest path, but the bead starts slowly. A curve that drops steeply first builds speed early, and that speed carries it the rest of the way. The best curve is a cycloid, the path traced by a point on a rolling wheel.

For a cycloid made by a wheel of radius r, a bead released from the top reaches the lowest point in t = π√(r/g), and it takes the same time from any starting point on the curve. With r = 1 m the trip takes about 1.0 s.

Newton, Leibniz and the Bernoulli brothers all solved it. The problem helped launch the calculus of variations, used today in physics and engineering.

Equations

\[t = \pi\sqrt{\frac{r}{g}}\]
Symbols
SymbolMeaningUnit
\(t\) descent time \(\mathrm{s}\)
\(r\) generating circle radius \(\mathrm{m}\)
\(g\) gravitational acceleration \(\mathrm{m/s²}\)