• Pixel-art sticker of Keplette, personifying Kepler's Third Law, with the caption “Wider Orbit, Longer Year.”

IndexRelativity & CosmosSticker

Keplette

Kepler's Third Law Physics

\[T^2 = \frac{4\pi^2}{GM}a^3\]
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Meet Keplette, who knows the square of an orbit's period grows as the cube of its size. In her art the outer orbit is 70/44 times wider, so its year is (70/44)^1.5, about 2.0 times longer. Pixel-art kiss-cut sticker in 2, 3, 4 and 6 inches; equation, symbols and sources in the physics panel below.

Size
Surface

Flat $6 shipping worldwideMade to order, ships in 2–5 business days

Details

Size3″ × 3″

3″ × 3″ kiss-cut sticker.

Shipping

Flat $6 shipping on every order, worldwide, whatever's in it.

Delivery times & where we ship

Returns & replacements21 days

Every item is printed to order, so we can’t accept returns or exchanges for change of mind, or if you ordered the wrong size or colour.

Print defect, misprint, damage or the wrong item? We’ll send a free replacement, or a refund if you prefer. Report it within 21 days of delivery with a photo; no need to send it back.

Full refund & replacement policy

The physics

Meet Keplette, a planet who knows that a bigger orbit means a much longer year.

Johannes Kepler found from Tycho Brahe's observations that a planet's orbital period T and the size of its orbit a are linked: T² is proportional to a³. He published this third law in 1619. Isaac Newton later derived it from his law of gravity and showed what the constant is: T² = 4π²a³/(GM), where M is the mass of the central body.

So doubling the orbit's size makes the year 2^1.5 ≈ 2.8 times longer. In the sticker the outer orbit is 70/44 times wider than the inner one, so its year is (70/44)^1.5 ≈ 2.0 times longer. Mars orbits at about 1.52 times Earth's distance, and its year is about 1.88 Earth years.

Run the law backwards and it weighs things: measure a moon's period and orbit and you get the planet's mass. The same method gives the masses of stars in binaries and of the black hole at the Milky Way's centre.

The simple form neglects the orbiting body's own mass. For two comparable masses, M is replaced by the total.

Equations

\[T^2 = \frac{4\pi^2}{GM}a^3\]
Symbols
SymbolMeaningUnit
\(T\) orbital period \(\mathrm{s}\)
\(a\) semi-major axis of the orbit \(\mathrm{m}\)
\(G\) Newtonian constant of gravitation \(\mathrm{N·m²/kg²}\)
\(M\) mass of the central body \(\mathrm{kg}\)