• Ignia Lawson Criterion pixel-art physics T-shirt, white tee, front view

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Ignia

The Lawson Criterion Physics

\[n\,T\,\tau_E \gtrsim 3\times10^{21}\ \mathrm{keV\,s\,m^{-3}} \quad (\text{D-T ignition; lowest near } T \approx 14\ \mathrm{keV})\]
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Size guide S–5XL · inches

Ignia holds a star in a bottle. To light it, she needs it dense enough, hot enough, for long enough.

The Physics

For a deuterium–tritium plasma to ignite, the product of density, temperature and energy confinement time must pass a threshold, lowest near 14 keV. Each fusion makes a 3.5 MeV helium nucleus, which stays to heat the plasma, and a 14.1 MeV neutron.

n T τ_E ≳ 3 × 10²¹ keV·s·m⁻³, D + T → ⁴He (3.5 MeV) + n (14.1 MeV)

  • n: ion density (m⁻³)
  • T: temperature (keV; 1 keV ≈ 11.6 million K)
  • τ_E: energy confinement time (s)
  • D, T: deuterium, tritium
  • n (in the reaction): neutron

J. D. Lawson set out the criterion in 1957; on 5 Dec 2022 the National Ignition Facility put 2.05 MJ of laser light on a target and got 3.15 MJ out, a target gain of about 1.5.

Honest caveat: The lasers drew about 100 times more energy from the grid. That was target gain, not net or wall-plug gain.

On the shirt

Front: Ignia, the pixel-art character, with the title. Back: the triple product, the D–T reaction, the NIF 2022 result and the wall-plug caveat. Printed on a unisex tee.

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Details

Size & fitS–5XL

Unisex heavy cotton (Gildan 5000), classic fit.

Unisex tee size chart, inches
SizeWidthLengthSleeve
S182815.1
M202916.5
L223018
XL243119.5
2XL263221
3XL283322.4
4XL303423.7
5XL323525

スケール感の目安:サイズ M の幅は 20 in(50.80 cm)で、プランク長のおよそ 3.143 × 1034 倍です(lP = 1.616255 × 10−35 m)。メジャーで測るほうが早いです。

Measurements in inches, ±1.5 in tolerance.

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Returns & replacements21 days

Every item is printed to order, so we can’t accept returns or exchanges for change of mind, or if you ordered the wrong size or colour.

Print defect, misprint, damage or the wrong item? We’ll send a free replacement, or a refund if you prefer. Report it within 21 days of delivery with a photo; no need to send it back.

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The physics

I hold a star in a bottle. To light it, I need it dense enough, hot enough, for long enough.

John Lawson set out the condition in 1957. For a deuterium–tritium plasma to ignite, the product of ion density, temperature and energy confinement time must pass about 3 × 10²¹ keV·s·m⁻³, and that threshold is lowest near 14 keV, roughly 160 million kelvin. Each fusion makes a 3.5 MeV helium nucleus, which stays to heat the plasma, and a 14.1 MeV neutron, which escapes.

On 5 December 2022 the National Ignition Facility put 2.05 MJ of laser light on a target and got about 3.15 MJ of fusion energy out, a target gain of about 1.5. That is target gain, not wall-plug gain: the lasers draw about 100 times more energy than reaches the target.

Equations

\[n\,T\,\tau_E \gtrsim 3\times10^{21}\ \mathrm{keV\,s\,m^{-3}} \quad (\text{D-T ignition; lowest near } T \approx 14\ \mathrm{keV})\]
\[\mathrm{D} + \mathrm{T} \rightarrow {}^{4}\mathrm{He}\ (3.5\ \mathrm{MeV}) + n\ (14.1\ \mathrm{MeV})\]
Symbols
SymbolMeaningUnit
\(n\) ion density \(\mathrm{1/m³}\)
\(T\) plasma temperature in energy units (1 keV ≈ 1.16 × 10⁷ K) \(\mathrm{keV}\)
\(\tau_E\) energy confinement time \(\mathrm{s}\)
\(\mathrm{D},\ \mathrm{T}\) deuterium and tritium nuclei \(\mathrm{1}\)
\({}^{4}\mathrm{He},\ n\) helium-4 nucleus and neutron (fusion products) \(\mathrm{1}\)